www.ijcrt.org © 2020 IJCRT | Volume 8, Issue 8 August 2020 | ISSN: 2320-2882
IJCRT2008303 International Journal of Creative Research Thoughts (IJCRT) www.ijcrt.org 2702
Invariant means of sequences with statistical behaviour
Abdul Hamid Ganie
1
Sameer Ahmad Gupkari
2
and Afroza Akhter
3
1,3
Department of Applied Sciences and Humanities, SSM College of Engineering
and Technology Pattan, Jammu and Kahsmir.
2
J & K Institute of Mathematical Sciences, Kashmir-India.
3
AlJanoub Internationational School, Asir-KSA.
Abstract: The current paper is thrusting to bring out some techniques of spaces by defining
and
∅
of sigma
strongly convergence in statistically nature and lacunary nature of convergent sequences of strong sigma statistically
in nature. Some basic topological properties will be given.
Mathematics Subject Classification [2010] : 46A45; 46CO5, 46B50.
Keywords: Sequences; summable nature; convergence.
1. Introduction and historical background: We call a sequence to be function whose domain is the set of natural
numbers. Let us represent as set of all real or complex sequences, so the sequence space is any subspace of .
With , and we designate the set of non-negative integers, the set of real numbers and the set of complex
numbers, respectively. Let
∞
, and
0
, respectively, designates the set of bounded sequences, convergent sequences
and those which has limit as zero [1], [8], 11-[15], [18]-[21].
Cesàro sums represents an “averaging” process. In 1890 the Italian mathematician Ernesto Cesàro used such sums
while investigating products of infinite series. A expansion of the type ∑
∞
=0
is said to be Cesaro summable to ∈
if and only if its Cesaro sum converges i.e.,
= ∑ [1 −
]
−1
=0
=
0
+
1
+⋯+
−1
=
1
∑
−1
=0
converges to as → ∞.
Thus, for a sequence
with ∑
∞
=0
= converges if and only if its sequence of partial sums
converges to i.e.,
given >0, we can find a natural number
0
∈ in such a way that ≥
0
implies |
− | < or equivalently, if
|
− | < then ∑
∞
=0
is Cesàro is summable [22]. Then, we can have
|
− | = |
0
+
1
+⋯+
−1
− | = |∑ [1 −
]
−1
=0
− |.