J. OPERATOR THEORY
58:2(2007), 351–386
© Copyright by THETA, 2007
A GENERAL FACTORIZATION APPROACH TO THE
EXTENSION THEORY OF NONNEGATIVE
OPERATORS AND RELATIONS
SEPPO HASSI, ADRIAN SANDOVICI, HENK DE SNOO, and HENRIK WINKLER
Communicated by Florian-Horia Vasilescu
ABSTRACT. The Kre˘ ın-von Neumann and the Friedrichs extensions of a non-
negative linear operator or relation (i.e., a multivalued operator) are character-
ized in terms of factorizations. These factorizations lead to a novel approach to
the transversality and equality of the Kre˘ ın-von Neumann and the Friedrichs
extensions and to the notion of positive closability (the Kre˘ ın-von Neumann
extension being an operator). Furthermore, all extremal extensions of the non-
negative operator or relation are characterized in terms of analogous factoriza-
tions. This approach for the general case of nonnegative linear relations in a
Hilbert space extends the applicability of such factorizations. In fact, the ex-
tension theory of densely and nondensely defined nonnegative relations or
operators fits in the same framework. In particular, all extremal extensions of
a bounded nonnegative operator are characterized.
KEYWORDS: Nonnegative relation, Friedrichs extension, Kre˘ ın-von Neumann ex-
tension, disjointness, transversality, positive closability, extremal extension.
MSC (2000): Primary 47A06, 47A57, 47A63, 47B25; Secondary 47A07, 47B65.
INTRODUCTION
To illustrate the factorizations introduced in this paper consider the follow-
ing simple completion problem. Let H be a Hilbert space with the orthogonal
decomposition H = H
1
⊕ H
2
. Let S
11
be a nonnegative bounded linear operator
in H
1
, let S
21
be a bounded linear operator from H
1
to H
2
, and let S
12
= S
∗
21
. The
usual form of the completion problem requires to determine all bounded linear
operators S
22
in H
2
, such that
(0.1)
S
11
S
12
S
21
∗
becomes a nonnegative bounded linear operator in H, cf. [7], [13], [16], [28], [29],
[33], [35]. This completion problem has a solution if and only if ran S
∗
21
⊂ ran S
1/2
11
.